The return data type is the data type of the date argument, except for string literals. I need to subtract a number of minutes from a date. As per the documentation, the return type of DATEADD is the same as the input: You need to consider how you want to handle calculations that lead to either or both and to be in the next day.Īlso - to address another new requirement in your "ideal answer" - there is no loss of precision. I assume this must go through some type of internal conversion, because you couldn't get that result by saying: DECLARE TIME(0) = '24:19' Ĭonversion failed when converting date and/or time from character string.
This doesn't yield an error, however, just might not be the result you're expecting. Try: DATEADD(MINUTE, that even though you have protected your from overflow, you haven't protected the result from overflow.
Inside another qurey, you'll wand something like (#Minus minutes in sql how to
You can't use lazy shorthand arithmetic with the new types. Anupama was showing you how to look at the results of your query to prove that the minutes were being subtracted. If there are no issues then please state so.
Issues or concerns to be aware of in the event that the minutes would be to too large to fit in a time variable, or risk of rolling the time variable over.That the proposed solution does not result in a loss of precision.How to add minutes to to a time data type.What is the correct way to add minutes to and note I am using the time data type.Ī correct answer should contain the following information: (/*Other columns*/ columns*/ + + ELSE does.*/ INSERT INTO ClientNotification (/*Other columns*/ startTime, endTime) SET = % 1440 -Prevent overflow if needed? I have a stored procedure which inserts two records into a table, the difference between the records is that the time column of the second record is after the first: CREATE PROCEDURE CreateEntry